Optional Lesson
This lesson is optional and will not count towards your achievement.
To view the completed code, check out the 11-movie-lists
branch.
In this challenge, you will implement the remaining methods in the MovieDAO
for retrieving a list of movies:
-
get_by_genre() - should return a paginated list of movies that are listed in a particular Genre
-
get_for_actor() - should return a paginated list of movies that a particular Person has acted in
-
get_for_director() - should return a paginated list of movies that a particular Person has directed
These methods are very similar to the all()
method which returns a full list, but with a different pattern in the MATCH
clause.
For each subtask, we will provide you with the pattern required to run in the Cypher statement, plus any additional parameters that are required for the query to run.
All you need to do is take the code from the all()
method of the MovieDAO
and modify the pattern in the first line of the Cypher statement in the first argument of the tx.run()
call, then if necessary add the additional parameters to the second argument.
If you get stuck at any point, you can click to reveal the completed solution or skip to the bottom for instructions on how to checkout the branch with the working solution.
get_by_genre()
The get_by_genre()
method returns a paginated list of movies that are listed within a certain genre.
def get_by_genre(self, name, sort='title', order='ASC', limit=6, skip=0, user_id=None):
# TODO: Get Movies in a Genre
# TODO: The Cypher string will be formated so remember to escape the braces: {{name: $name}}
# MATCH (m:Movie)-[:IN_GENRE]->(:Genre {name: $name})
return popular[skip:limit]
Update the get_by_genre()
method to use the following Cypher Pattern:
MATCH (m:Movie)-[:IN_GENRE]->(:Genre {name: $name})
The tx.run()
call will need to include the name
property, which represents the name of the genre.
Click to reveal the completed get_by_genre()
method
Find the get_by_genre()
method in api/dao/movies.py
and modify the function to find a list of movies by genre.
def get_by_genre(self, name, sort='title', order='ASC', limit=6, skip=0, user_id=None):
# Get Movies in a Genre
def get_movies_in_genre(tx, sort, order, limit, skip, user_id):
favorites = self.get_user_favorites(tx, user_id)
cypher = """
MATCH (m:Movie)-[:IN_GENRE]->(:Genre {{name: $name}})
WHERE m.`{0}` IS NOT NULL
RETURN m {{
.*,
favorite: m.tmdbId in $favorites
}} AS movie
ORDER BY m.`{0}` {1}
SKIP $skip
LIMIT $limit
""".format(sort, order)
result = tx.run(cypher, name=name, limit=limit, skip=skip, user_id=user_id, favorites=favorites)
return [ row.get("movie") for row in result ]
with self.driver.session() as session:
return session.execute_read(get_movies_in_genre, sort, order, limit=limit, skip=skip, user_id=user_id)
get_for_actor()
The get_for_actor()
method returns a paginated list of movies that a person has acted in.
def get_for_actor(self, id, sort='title', order='ASC', limit=6, skip=0, user_id=None):
# TODO: Get Movies for an Actor
# TODO: The Cypher string will be formated so remember to escape the braces: {{tmdbId: $id}}
# MATCH (:Person {tmdbId: $id})-[:ACTED_IN]->(m:Movie)
return popular[skip:limit]
Find the get_for_actor()
method in api/dao/movies.py
and modify the function to find a list of movies by actor.
The pattern required in the MATCH
clause will be:
MATCH (:Person {tmdbId: $id})-[:ACTED_IN]->(m:Movie)
You will have to include the additional parameter id
- The tmdbId
property relating to the actor.
Click to reveal the completed getForActor()
method
def get_for_actor(self, id, sort='title', order='ASC', limit=6, skip=0, user_id=None):
# Get Movies for an Actor
def get_movies_for_actor(tx, id, sort, order, limit, skip, user_id):
favorites = self.get_user_favorites(tx, user_id)
cypher = """
MATCH (:Person {{tmdbId: $id}})-[:ACTED_IN]->(m:Movie)
WHERE m.`{0}` IS NOT NULL
RETURN m {{
.*,
favorite: m.tmdbId in $favorites
}} AS movie
ORDER BY m.`{0}` {1}
SKIP $skip
LIMIT $limit
""".format(sort, order)
result = tx.run(cypher, id=id, limit=limit, skip=skip, user_id=user_id, favorites=favorites)
return [ row.get("movie") for row in result ]
with self.driver.session() as session:
return session.execute_read(get_movies_for_actor, id, sort, order, limit=limit, skip=skip, user_id=user_id)
get_for_director()
The get_for_director()
method returns a paginated list of movies that a person has directed.
def get_for_director(self, id, sort='title', order='ASC', limit=6, skip=0, user_id=None):
# TODO: Get Movies directed by a Person
# TODO: The Cypher string will be formated so remember to escape the braces: {{name: $name}}
# MATCH (:Person {tmdbId: $id})-[:DIRECTED]->(m:Movie)
return popular[skip:limit]
Find the getForDirector()
method in api/dao/movies.py
and modify the function to find a list of movies by director.
The pattern required in the MATCH
clause will be:
MATCH (:Person {tmdbId: $id})-[:DIRECTED]->(m:Movie)
You will have to include the additional parameter id
- The tmdbId
property relating to the director.
Click to reveal the completed get_for_director()
method
def get_for_director(self, id, sort='title', order='ASC', limit=6, skip=0, user_id=None):
# Get Movies directed by a Person
def get_movies_for_director(tx, id, sort, order, limit, skip, user_id):
favorites = self.get_user_favorites(tx, user_id)
cypher = """
MATCH (:Person {{tmdbId: $id}})-[:DIRECTED]->(m:Movie)
WHERE m.`{0}` IS NOT NULL
RETURN m {{
.*,
favorite: m.tmdbId in $favorites
}} AS movie
ORDER BY m.`{0}` {1}
SKIP $skip
LIMIT $limit
""".format(sort, order)
result = tx.run(cypher, id=id, limit=limit, skip=skip, user_id=user_id, favorites=favorites)
return [ row.get("movie") for row in result ]
with self.driver.session() as session:
return session.execute_read(get_movies_for_director, id, sort, order, limit=limit, skip=skip, user_id=user_id)
Testing
To test that this functionality has been correctly implemented, run the following code in a new terminal session:
pytest -s tests/11_movie_lists__test.py
The test file is located at tests/11_movie_lists__test.py
.
Are you stuck? Click here for help
If you get stuck, you can see a working solution by checking out the 11-movie-lists
branch by running:
git checkout 11-movie-lists
You may have to commit or stash your changes before checking out this branch. You can also click here to expand the Support pane.
Verifying the Test
1. How many films has Francis Ford Copolla directed?
The last test within the test suite will log out the number of results returned from the API for films directed by Francis Ford Copolla.
Enter the number in the box below and click Check Answer.
-
✓ 16
Hint
You can also find the answer by running the following Cypher statement:
MATCH (p:Person {tmdbId: "1776"})
RETURN count { (p)-[:DIRECTED]->() }
Copy the answer without any quotes or whitespace.
Lesson Summary
In this Challenge, you modified the functions in the MovieDAO
to return lists of movies.
In the next Challenge, you will implement the find_by_id()
method.